Задача №692
Докажите тождество:
а) (х - 3)(х + 7) - 13 = (х + 8)(х - 4) - 2;
б) 16 - (а + 3)(а + 2) = 4 - (6 + а)(а - 1).
Решение задачи №692:
1692. | a) (x - 3)(x + 7) - 13 = x2 + 7x - 3x -= x2+4x —34, (x+8)(x-4)-2 = x2-4x+8x-= x2+4x — 34 => (x — 3)(x+7) —13 = (x+8)(x 6) 16—(a+3)(a+2) = 16—a2—2a—3a—6 = -a2 4 — (6 + a)(a — 1) = 4 — 6a+ 6 — a2 + a — —a + 10 =» 16 - (a + 3)(a + 2) = 4 - (6 + a)(a -
1- 13 = 32-2 = — 4) —2; -5a+10, 2 — 5a + !)•
Оцените это ГДЗ:
Error: Table './admin_math_fivestar/ratings' is marked as crashed and last (automatic?) repair failed | 
