Задача №793
Разложите на множители многочлен:
а) х2 - 10x + 24; в) х2 + 8х + 7; д) х2 + х - 12;
б) х2 - 13x + 40; г) х2 + 15x + 54; е) х2 - 2х - 35.
Решение задачи №793:
1793. | a) x2 — 10x + 24 = x2-6x-4x + 24 = x-(x-4)-
- 6 ¦ (x - 4) = (x - 6)(x - 4); 6) x2 - 13x + 40 = x2-
- 5x - 8x + 40 = x • (x - 5) - 8 • (x - 5) = (x - 8)(x — 5); в) x2 + 8x + 7 = x2 + 7x + x + 7 = x • (x + 7) + (x + + 7) = (x + 1) (+ 7); r) x2 + 15x + 54 = x2 + 9x + + 6x + 54 = x • (x + 9) + 6 • (x + У) = (x + 6)(x + 9);
д) x2 + x - 12 = x2 - 3x + 4x - 12 = x - (x - 3) + 4x x (x - 3) = {x + 4)(x — 3); e) x2-2x-35 = x2 — 7x + + 5x — 35 = x • (x - 7) + 5 ¦ (x — 7) = (x + 5)(x — 7).
Оцените это ГДЗ:
Error: Table './admin_math_fivestar/ratings' is marked as crashed and last (automatic?) repair failed | 
